问

Django:ajax调用的login_required

妈妈说称号长的人很牛也发布于 2023-01-19 19:50

ajax

settings

request

function

我试图在ajax帖子上验证用户,但不起作用.这就是我所做的

settings.py

LOGIN_URL = '/accounts/login/'
LOGIN_REDIRECT_URL = '/'

模板

urls.py

url(r'^like/$', 'apps.quotation.views.like', name='like'),

views.py - 尝试1

@login_required
def like(request):
        vars = {}
        if request.method == 'POST':
            response_dict = {}

            if not something:
                response_dict.update({'message': "Requested" })
            else:
                response_dict.update({'message': "You have already requested" })

        return HttpResponse(simplejson.dumps(response_dict),
                        mimetype='application/javascript')

views.py - 尝试2

def like(request):
    if not request.user.is_authenticated():
        return HttpResponseRedirect('/accounts/login')
    else:
        vars = {}
        if request.method == 'POST':
            response_dict = {}
            if not something:
                response_dict.update({'message': "Requested" })
            else:
                response_dict.update({'message': "You have already requested" })

        return HttpResponse(simplejson.dumps(response_dict),
                        mimetype='application/javascript')

运行服务器日志

[05/Mar/2014 05:19:16] "POST /like/ HTTP/1.1" 302 0
[05/Mar/2014 05:19:16] "GET /accounts/login/?next=/like/ HTTP/1.1" 200 5610

我错过了什么？

2 个回答

当我想检查当用户登录时进行Ajax调用时,我使用的是:
```
from functools import wraps
from django.core.exceptions import PermissionDenied

def ajax_login_required(view):
    @wraps(view)
    def wrapper(request, *args, **kwargs):
        if not request.user.is_authenticated():
            raise PermissionDenied
        return view(request, *args, **kwargs)
    return wrapper
```
raise PermissionDenied将导致403状态代码返回给客户端.否则,如果您使用@login_required装饰器或手动重定向到表单,那么Ajax调用看作响应的内容对于人类是有意义的,但对于Ajax调用没有意义.
2023-01-19 19:52 回答

羽靜幻雲_100

代替 :

if not request.user.is_authenticated():
   return HttpResponseRedirect('/accounts/login')

返回json响应:

if request.user.is_authenticated():
    ## write your code...
    jsonr = json.dumps({ 'authenticated': True })
    return HttpResponse(jsonr, mimetype='application/json')
else:
    jsonr = json.dumps({ 'authenticated': False })
    return HttpResponse(jsonr, mimetype='application/json')

在您的ajax成功响应中,如果未经过身份验证,则重定向到使用登录windows.location.

或者您可以编写装饰器: Django身份验证和Ajax - 需要登录的URL

2023-01-19 19:52 回答

mobiledu2502899415

撰写答案

今天，你开发时遇到什么问题呢？

立即提问

热门标签