存储指向方法的派生指针

你不能.A没有方法new_function,你对编译器撒谎.你有三种方法

1.

移动new_function到A并通过A::new_function(作为virtual优选).

class A
{
    void (A::*curr_f)();
public:
    void set(void (A::*f)())
    {
        curr_f = f;
    }
    virtual void new_function() {};
};

class B : A
{
public:
    void main()
    {
        set(&A::new_function);
    };
    void new_function() {};
};

2.

转发B声明和存储B::*在A:

class B;

class A
{
    void (B::*curr_f)();
public:
    void set(void (B::*f)())
    {
        curr_f = f;
    }
};

class B : A
{
public:
    void main()
    {
        set(&B::new_function);
    }
    void new_function() {}
};

3.

您可以尝试基于模板的方式,例如奇怪的重复模板模式(CRTP).

template <typename D>
class A
{
    void (D::*curr_f)();
public:
    void set(void (D::*f)())
    {
        curr_f = f;
    }
};

class B : public A<B>
{
public:
    void main()
    {
        set(&B::new_function);
    }
    void new_function() {}
};