我正试图在jmeter测试中提取一部分html.
我需要从
我只需要:
%3b%3bAjaxControlToolkit%2c+Version%3d1.0.11119.38311%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3apt-BR%3adf9c6e46-ef8c-4a3d-89af-f80adf22e9c2%3a865923e8%3a411fea1c%3ae7c87f07%3a91bd373d%3a1d58b08c%3a8e72a662%3aacd642d2%3a596d588c%3a77c58d20%3a14b56adc%3a269a19ae
现在我创建了这个正则表达式:
%3b.*"
匹配:
%3b%3bAjaxControlToolkit%2c+Version%3d1.0.11119.38311%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3apt-BR%3adf9c6e46-ef8c-4a3d-89af-f80adf22e9c2%3a865923e8%3a411fea1c%3ae7c87f07%3a91bd373d%3a1d58b08c%3a8e72a662%3aacd642d2%3a596d588c%3a77c58d20%3a14b56adc%3a269a19ae"
但我不想要最后两个字符(一个空格)和"
.
如何删除最后两个字符?
使用正则表达式模式
%[^"]+
也许积极的前瞻可能有所帮助,例如:
%3b.*(?="\s)