我在这里关注Celery First Steps教程:http://celery.readthedocs.org/en/latest/getting-started/first-steps-with-celery.html#keeping-results
我正在使用RabbitMQ继续学习本教程.
当我在做result.get(timeout = 1)时,它显示一个超时错误,即使它是一个简单的添加操作,我可以看到工作者在另一个窗口中运行并产生正确的结果(8)
(venv) C:\Volt\celerytest>ipython Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)] Type "copyright", "credits" or "license" for more information. IPython 2.1.0 -- An enhanced Interactive Python. ? -> Introduction and overview of IPython's features. %quickref -> Quick reference. help -> Python's own help system. object? -> Details about 'object', use 'object??' for extra details. In [1]: from tasks import add In [2]: a = add(1,3) In [3]: a Out[3]: 4 In [4]: a = add.delay(1,3) In [5]: a.ready() Out[5]: False In [6]: a = add.delay(4,4) In [7]: a.get(timeout=0.5) --------------------------------------------------------------------------- TimeoutError Traceback (most recent call last)in () ----> 1 a.get(timeout=0.5) C:\Users\Som\Envs\venv\lib\site-packages\celery\result.pyc in get(self, timeout, propagate, interval, no_ack, follow_parents) 167 interval=interval, 168 on_interval=on_interval, --> 169 no_ack=no_ack, 170 ) 171 finally: C:\Users\Som\Envs\venv\lib\site-packages\celery\backends\amqp.pyc in wait_for(se lf, task_id, timeout, cache, propagate, no_ack, on_interval, READY_STATES, PROPA GATE_STATES, **kwargs) 155 on_interval=on_interval) 156 except socket.timeout: --> 157 raise TimeoutError('The operation timed out.') 158 159 if meta['status'] in PROPAGATE_STATES and propagate: TimeoutError: The operation timed out. In [8]:
tasks.py文件
from celery import Celery app = Celery('tasks', backend='amqp', broker='amqp://') @app.task def add(x, y): return x + y
工人日志
[tasks] . tasks.add [2014-07-17 13:00:33,196: INFO/MainProcess] Connected to amqp://guest:**@127.0.0 .1:5672// [2014-07-17 13:00:33,211: INFO/MainProcess] mingle: searching for neighbors [2014-07-17 13:00:34,220: INFO/MainProcess] mingle: all alone [2014-07-17 13:00:34,240: WARNING/MainProcess] celery@SomsPC ready. [2014-07-17 13:00:34,242: INFO/MainProcess] Received task: tasks.add[85ff75d8-38 b5-442a-a574-c8b976a33739] [2014-07-17 13:00:34,243: INFO/MainProcess] Task tasks.add[85ff75d8-38b5-442a-a5 74-c8b976a33739] succeeded in 0.000999927520752s: 4 [2014-07-17 13:00:46,582: INFO/MainProcess] Received task: tasks.add[49de7c6b-96 72-485d-926e-a4e564ccc89a] [2014-07-17 13:00:46,588: INFO/MainProcess] Task tasks.add[49de7c6b-9672-485d-92 6e-a4e564ccc89a] succeeded in 0.00600004196167s: 8
Sergey Petru.. 5
经过'芹菜第一步'后,我遇到了完全相同的问题.
我认为建议这样做的原因backend='amqp'
.
对我有用的设置如下:
app = Celery('tasks', broker='amqp://guest@localhost//') app.conf.CELERY_RESULT_BACKEND = 'db+sqlite:///results.sqlite'
根据文档,当使用AMQP结果后端时,每个结果只能被检索一次(它实际上是查询中的单个消息).
我想,你的工作进程检索它以便将结果打印到控制台:
Task tasks.add[49de7c6b-9672-485d-926e-a4e564ccc89a] succeeded in 0.00600004196167s: 8
所以你无法再次检索相同的结果.