问

Angular Js文件上传

bl乄ue光耀发布于 2023-02-12 18:14

上传

我是棱角分明的新手.我想用这个上传文件.我使用以下链接

http://jsfiddle.net/jasonals/WEvwz/27/？upload.html





  
      
      
          
              {{file.name}}
          
      
  

  


controlller file.
$(document).ready(function(){
    $('#fileupload').fileupload({
        dataType: 'json'});
});

TestCtrl = function($scope){
    $scope.fileList = [];
    $('#fileupload').bind('fileuploadadd', function(e, data){
        // Add the files to the list
        numFiles = $scope.fileList.length
        for (var i=0; i < data.files.length; ++i) {
            var file = data.files[i];
        // .$apply to update angular when something else makes changes
        $scope.$apply(
            $scope.fileList.push({name: file.name})
            );
        }
        // Begin upload immediately
        data.submit();
    });
    $scope.addButtonClicked = function(){
        var numFiles = $scope.fileList.length;
        $scope.fileList.push({name: ('fileName' + numFiles)});
    }
}

但我无法使用此发布网址.

1 个回答

我不能直接回答你的问题,除了说:确保你data-url在JSFiddle的例子中输入你的输入.

作为替代方案,我建议使用我成功使用的angular-file-upload.它使用角度指令来完成上传.这种模式使用了更多的代码,但是将应用程序中的问题分开,这样Controller就可以将事物粘合在一起,并且您的服务实际上与外部世界进行对话.

这将使您的应用程序更容易测试:

<div ng-controller="FileUploadController">
  <h3>Upload a file</h3>
  <input type="file" ng-file-select="uploadFile($files)" />
</div>

和javascript:

// define the app, include the file upload dependency
var app = angular.module('MyApp', ['ng', 'angularFileUpload']);

// controller to handle the file upload event
app.controller('FileUploadController', 
  function ($scope, $rootScope, FileUploadService) {
    var service = FileUploadService;
    /** 
     *  Handler to upload a new file to the server.
     */
    $scope.uploadFile = function ($files) {
      var $file = $files[0];
      service.uploadFile($file, function (error) {
        if (error) {
          alert('There was a problem uploading the file.');
        }
        // handle successfully-uploaded file
      })
    }
  });

// services should interact with the outside world
app.factory('FileUploadService', function ($http) {
  var api = {
    uploadFile: function (file, callback) {
      $http.uploadFile({
        url: '/some/remote/end/point/',
        file: file
      }).progress(function(event) {
        console.log('percent: ' + parseInt(100.0 * event.loaded / event.total));
      }).error(function (data, status, headers, config) {
        console.error('Error uploading file')
        callback(status);
      }).then(function(data, status, headers, config) {
        callback(null);
      });
    }
  }
  return api;
});

2023-02-12 18:18 回答

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