问

Android蓝牙UUID将APP连接到ANDROID

爱被结束_347 发布于 2023-01-30 13:26

android

我正在构建一个Android应用程序,它可以在设备上保留蓝牙连接的跟踪,并在超出范围时触发警报.

Android文档要求UUID以建立连接.

'uuid'是用于唯一标识信息的字符串ID的通用唯一标识符(UUID)标准化128位格式.它用于唯一标识应用程序的蓝牙服务.

 public ConnectThread(BluetoothDevice device) {
    // Use a temporary object that is later assigned to mmSocket,
    // because mmSocket is final
    BluetoothSocket tmp = null;
    mmDevice = device;

    // Get a BluetoothSocket to connect with the given BluetoothDevice
    try {
        // MY_UUID is the app's UUID string, also used by the server code
        tmp = device.createRfcommSocketToServiceRecord(MY_UUID);
    } catch (IOException e) { }
    mmSocket = tmp;
}

我没有在两个设备上安装应用程序,所以我没有设置我自己的UUID,我想使用android的代替......但我无法在任何地方的文档中找到它.

也许我没有正确地解决问题.任何帮助将不胜感激.提前致谢

1 个回答

您可以从BluetoothDevice获取UUID

    mmDevice = device;

    // Get a BluetoothSocket to connect with the given BluetoothDevice. This code below show how to do it and handle the case that the UUID from the device is not found and trying a default UUID.

    // Default UUID
    private UUID DEFAULT_UUID = UUID.fromString("00001101-0000-1000-8000-00805F9B34FB"); 

    try {
        // Use the UUID of the device that discovered // TODO Maybe need extra device object
        if (mmDevice != null)
        {
            Log.i(TAG, "Device Name: " + mmDevice.getName());
            Log.i(TAG, "Device UUID: " + mmDevice.getUuids()[0].getUuid());
            tmp = device.createRfcommSocketToServiceRecord(mmDevice.getUuids()[0].getUuid());

        }
        else Log.d(TAG, "Device is null.");
    }
    catch (NullPointerException e)
    {
        Log.d(TAG, " UUID from device is null, Using Default UUID, Device name: " + device.getName());
        try {
            tmp = device.createRfcommSocketToServiceRecord(DEFAULT_UUID);
        } catch (IOException e1) {
            e1.printStackTrace();
        }
    }
    catch (IOException e) { }

2023-01-30 13:28 回答

13578945682a_699

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