问

Android HTTP Get

fishandyp 发布于 2023-02-13 14:56

php

我看了一些论坛帖子,我无法找到问题的答案.我想从一个php文件得到一个响应.php文件正常运行.问题是Android App不会执行我的请求.以下是我的代码的两个示例以及我在textview中得到的结果:

public void changText(View view) {
    TextView textv = (TextView)findViewById(R.id.textview1);
    textv.setText("Text Has Been Changed");
    BufferedReader in = null;
    String data = null;

    try{
           HttpClient httpclient = new DefaultHttpClient();

           HttpGet request = new HttpGet();
           URI website = new URI("http://alanhardin.comyr.com/matt24/matt28.php");
           request.setURI(website);
           HttpResponse response = httpclient.execute(request);
           in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

           textv.append(" Connected ");
       }catch(Exception e){
           Log.e("log_tag", "Error in http connection "+e.toString());
       }


   }

TextView显示:文本已更改

    public void changText(View view) {
    TextView textv = (TextView)findViewById(R.id.textview1);
    textv.setText("Text Has Been Changed");
    BufferedReader in = null;
    String data = null;

    try{
           HttpClient httpclient = new DefaultHttpClient();

           HttpGet request = new HttpGet();
           URI website = new URI("http://alanhardin.comyr.com/matt24/matt28.php");
           request.setURI(website);
           //HttpResponse response = httpclient.execute(request);
           //in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

           textv.append(" Connected ");
       }catch(Exception e){
           Log.e("log_tag", "Error in http connection "+e.toString());
       }


   }

TextView显示:文本已更改已连接

在这个清单中我有:

在错误日志中,我得到以下内容:http连接android.os.NetworkOnMainThreadException错误

任何帮助,将不胜感激.

1 个回答

Android可能正好执行您的请求.您似乎忽略了服务器返回的数据.你可以做这样的事情,例如:

public void changText(View view) {
    TextView textv = (TextView)findViewById(R.id.textview1);
    textv.setText("Text Has Been Changed");
    BufferedReader in = null;
    String data = null;

    try{
           HttpClient httpclient = new DefaultHttpClient();

           HttpGet request = new HttpGet();
           URI website = new URI("http://alanhardin.comyr.com/matt24/matt28.php");
           request.setURI(website);
           HttpResponse response = httpclient.execute(request);
           in = new BufferedReader(new InputStreamReader(
                   response.getEntity().getContent()));

           // NEW CODE
           String line = in.readLine();
           textv.append(" First line: " + line);
           // END OF NEW CODE

           textv.append(" Connected ");
       }catch(Exception e){
           Log.e("log_tag", "Error in http connection "+e.toString());
       }
}

看起来你的服务器正在返回一个JSON对象,所以你可能想要做一些更聪明的事情,比如读取整个响应,解析它(使用new JSONArray(response)),并提取相关字段,但上面的代码至少会验证Android是执行您的查询.

编辑:从您报告的异常,您似乎在主UI线程上运行您的代码.截至API 11被禁止(并且在此之前不赞成).有几篇关于如何解决这个问题的文章.请参阅指南主题无痛线程以及此处和此处的教程.另请参阅此主题以获取更多信息.

2023-02-13 14:58 回答

淼淼L玖兰枢

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