作者:凌彩霞_685 | 来源:互联网 | 2018-04-24 21:52
mysql_select_db($database_member,$member);$dizhimysql_query("SELECT*FROMmemberWHEREusernamelike'"+$row_Recordset1['articles_author']+"'");$rowmysql_fetch_array($dizhi);结果报错了mysql_fetch_array():s
变量selectphp
mysql_select_db($database_member, $member);
$dizhi= mysql_query("SELECT * FROM member WHERE username like '"+ $row_Recordset1['articles_author'] +"'");
$row = mysql_fetch_array($dizhi);
结果报错了
mysql_fetch_array(): supplied argument is not a valid MySQL result resource
求解决办法