HTML代码：-PHP源码

HTML代码：

jQuery框架AJAX返回JSON数据

PHP代码：
if($_GET['inajax'])
{

$arr = array(
array('name' => 'Richmond', 'nick' => iconv('gbk','utf-8','财富星空')),
array('name' => '343548', 'nick' => iconv('gbk','utf-8','笨笨草')),
array('name' => 'iceblue', 'nick' => iconv('gbk','utf-8','冰蓝'))
);
$json_string = json_encode($arr);
echo $json_string;

//echo '


';
//$obj = json_decode($json_string,true);
//print_r($obj);

}
?>