替换列表中的单词并附加到相同的列表

我已经制作了一个按预期工作的小代码:

city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
    for ii in comwo:
        if ii in c:
            city.append(city[i].replace(ii,""))
print(city)

输出:

['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']

注意:

您所做的列表包含错误的拼写.
查看list city的第一个元素VenangoMuniciplaity和common_words的第二个元素municipality

因此,如果您还想替换单词后面的空格(如果有的话),那么我已经创建了一个单独的代码:

[city.append(city[i].replace(ii,"")) for ii in comwo for i, c in enumerate(city) if ii in c]

输出:

city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
    for ii in comwo:
        if ii in c:
            city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)

我建议你使用以下解决方案,使用re.subwith flags=re.IGNORECASE来删除忽略大小写的常用词:

import re

city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']

toAppend = []

for c in city:
    for cw in common_words:
        if cw.lower() in c.lower().split():
            toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())

city += toAppend

print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']

这是使用列表理解的单行样式解决方案,简短但可读性较差:

import re

city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']

city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]

print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']

您可以尝试它,创建新列表以保存数据应该添加到您的原始列表,然后连接结果:

In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']

In [2]: common_words = ['ship', 'municiplaity']

In [3]: list_add = []

In [4]: for item in city:
   ...:     item_words = [s.lower() for s in item.split(' ')]
   ...:     if set(common_words) & set(item_words):
   ...:         new_item = [s for s in item.split(' ') if s.lower() not in common_words]
   ...:         list_add.append(" ".join(new_item))
   ...:         

In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']